R-NH2 + Cl-SO2-Ar-NHCOCH3 ------> R-NH-SO2-Ar-NHCOCH3
here the solvents i used where ... Acetic anhydride and Pyridine ... i have one article which says pyridine alone isnt strong enough to help the removal of proton as HCl quickly ... but when used with ac. anhyd. it forms a "N-acetyl pyridium complex" .. since the acetate ion is a comparatively stronger base
WHAT THE HECK IS A "N-acetyl pyridium complex"
i have tried my BEST to structure out the mechanism without any success ..
PLEASE HELP ME GUYSSSSSSSS !!!!