Topic: Moles to Grams (Read 3704 times)

Laafo · « **on:** November 04, 2009, 04:02:16 PM »

If a sample of CH3OH is found to contain 5.80x10^(-2) mol of O atoms how many grams of C atoms are present?

I have no idea how to do this problem, can anybody explain? Thanks!

Borek · « **Reply #1 on:** November 04, 2009, 04:07:14 PM »

How many moles of CH₃OH?

How many moles of C?

Laafo · « **Reply #2 on:** November 04, 2009, 04:09:26 PM »

Um, that's all the information I have, other than:
Molar Mass (g/mol)
NaOH   40.007
Na+ ion   23.000
OH- ion   17.007
Avogadro's No. (mol-1)
6.022×1023

sjb · « **Reply #3 on:** November 04, 2009, 05:05:03 PM »

Quote from: Laafo on November 04, 2009, 04:09:26 PM

Um, that's all the information I have, other than:
Molar Mass (g/mol)
NaOH   40.007
Na+ ion   23.000
OH- ion   17.007
Avogadro's No. (mol-1)
6.022×10²³

Why do you need the molar mass of NaOH?

csrscience.com · « **Reply #4 on:** November 04, 2009, 09:29:24 PM »

Notice that the the Carbon and oxygen are in a 1:1 ratio...

If you have 5.80x10^(-2) mol of Oxygen, why wouldn't you have 5.80x10^(-2) mol of carbon?

Hmmm!

Also notice that the CH3OH and O are also into a 1:1 ratio... what does this say about how many moles of CH3OH you have?

Topic: Moles to Grams (Read 3704 times)

Laafo

Moles to Grams

Borek

Re: Moles to Grams

Laafo

Re: Moles to Grams

sjb

Re: Moles to Grams

csrscience.com

Re: Moles to Grams

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