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January 10, 2025, 10:41:20 PM
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brominations at both ends of a 6 carbon chain ?
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Topic: brominations at both ends of a 6 carbon chain ? (Read 2731 times)
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hpl912
Regular Member
Posts: 25
Mole Snacks: +0/-0
brominations at both ends of a 6 carbon chain ?
«
on:
November 10, 2009, 09:18:16 PM »
I don't get by which method i can successfully obtain Br-(CH2)6-Br from CH3-(CH2)4-CH3
I was thinking by using Br2 with heat but that doesn't seem to double brominate the chain at both ends but i think it only brominates at one end and still it's a minor product (tends to attach only to the most substituted carbon)
i'm out of ideas now
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darkness1102
Regular Member
Posts: 20
Mole Snacks: +1/-3
Re: brominations at both ends of a 6 carbon chain ?
«
Reply #1 on:
November 10, 2009, 10:03:41 PM »
You should start from phenol (C
6
H
5
OH)
C
6
H
5
OH + H
2
/Ni --> C
6
H
11
OH --t
o
--> C
6
H
10
--( O
3
/H
2
O)--> OHC-(CH
2
)
4
-CHO -( LiAlH
4
)--> HO-CH
2
-(CH
2
)
4
-CH
2
-OH --(HBr)-->
Br-(CH
2
)
6
-Br
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hpl912
Regular Member
Posts: 25
Mole Snacks: +0/-0
Re: brominations at both ends of a 6 carbon chain ?
«
Reply #2 on:
November 11, 2009, 08:41:50 PM »
thanks but the starting material has to be CH3-(CH2)4-CH3
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brominations at both ends of a 6 carbon chain ?