From the following data at 25°C.
½H2(g) + ½O2(g) --> OH(g) ΔH° = 38.95 kJ/mol
H2(g) + ½O2(g) --> H2O(g) ΔH° = -241.81 kJ/mol
H2(g) --> 2H(g) ΔH° = 435.99 kJ/mol
O2(g) --> 2O(g) ΔH° = 498.34 kJ/mol
Compute the following:
ΔH° for OH(g) --> H(g) + O(g)
ΔU° for OH(g) --> H(g) + O(g)
ΔH° for H2O(g) --> 2H(g) + O(g)
ΔU° for H2O(g) --> 2H(g) + O(g)
ΔH° for H2O(g) --> H(g) + OH(g)
ΔU° for H2O(g) --> H(g) + OH(g)
I'm not sure how to do this question. I don't know how to rearrange and cancel. Please help.