[anon13]

From the following data at 25°C.

½H2(g) + ½O2(g) --> OH(g)              ΔH° = 38.95 kJ/mol
H2(g) + ½O2(g) --> H2O(g)              ΔH° = -241.81 kJ/mol
H2(g) --> 2H(g)                              ΔH° = 435.99 kJ/mol
O2(g) --> 2O(g)                              ΔH° = 498.34 kJ/mol

Compute the following:
ΔH° for OH(g) --> H(g) + O(g)
ΔU° for  OH(g) --> H(g) + O(g)
ΔH° for H2O(g) --> 2H(g) + O(g)
ΔU° for H2O(g) --> 2H(g) + O(g)
ΔH° for H2O(g) --> H(g) + OH(g)
ΔU° for H2O(g) --> H(g) + OH(g)

I'm not sure how to do this question. I don't know how to rearrange and cancel. Please help.

[anon13]

I take it nobody else knows how to do this question either? 

[sjb]

From the following data at 25°C.

½H₂(g) + ½O₂(g) --> OH(g)              ΔH° = 38.95 kJ/mol

OK, so what would ΔH° be for the reaction OH(g)  ½H₂(g) + ½O₂(g) ?

H₂(g) + ½O₂(g) --> H₂O(g)              ΔH° = -241.81 kJ/mol
H₂(g) --> 2H(g)                              ΔH° = 435.99 kJ/mol
O₂(g) --> 2O(g)                              ΔH° = 498.34 kJ/mol

Or for ½O₂(g) --> O(g)?

So what would be the ΔH° be for  OH(g)  ½H₂(g) + O(g) ?

Compute the following:
ΔH° for OH(g) --> H(g) + O(g)
ΔU° for  OH(g) --> H(g) + O(g)
ΔH° for H2O(g) --> 2H(g) + O(g)
ΔU° for H2O(g) --> 2H(g) + O(g)
ΔH° for H2O(g) --> H(g) + OH(g)
ΔU° for H2O(g) --> H(g) + OH(g)

I'm not sure how to do this question. I don't know how to rearrange and cancel. Please help.

[anon13]

After a lot of hard work, I finally got those answers! =)

I'm having difficulty with this one though