[mt055]

Hey, so i got a practice sheet of questions with no answers...so i just want to know if im doing these right, thanks
- 459ml of .242 M HCL is mixed with 273 ml of .198 M Mg(OH)2. What is the pH of the resulting mixture

acid
(.459 L )(.242 M) = .111078 mol HCl

(.111078)(1 H/1HCl) = .111078 mol H

Base
(.273 L)(.198M) = .054054 mol Mg(OH)2

(.054054)(2OH/1Mg(OH)2) = .108108 OH

.111078 - .108108 = .00297 excess H

.00297/.732L = .00405 H

pH = -log(4.05) + - log(10^-3)

pH = 2.39 ?

if someone could let me know if i did the steps right that'd be awesome, thanks!

[AWK]

Seems to be OK. But not using a ionic strength correction it is better to round result to 1 decimal point since real pH of your solution will be close to 2.5