[OrgoBorgo]

Hello again!
I just want to say I love this forum, it's very helpful and I'm glad I joined.
Now that I'm done kissing ass I have a question.

I've determined that 5-cholesten-3-one (C₂₇H₄₄O₁ has a degree of unsaturation of 6.

DOU = [(#carbons x2 +2 +halogens) - (#observed hydrogens + halogens)] / 2 = 6

Degree of unsaturation accounts for the number of rings + db/tp etc..
However, I see 4 rings and 1 double bond. So am i supposed to account for the double bond to oxygen in order to provide the correct DOU of 6 instead of 5 (4 rings + 1 c=c)?

Thanks!

Steve, (OrgoBorgo).

[darkness1102]

6 is correc, (27.2+2 -44)/2 =6. two duoble bonds ( C=O and C=C)  and 4 rings.