[JEE10]

What is the structure of S4O6 (2-) ?

The actual question was to find the oxidation state of each sulphur atom, but I did not know its structure.

[UG]

You don't need the structure in order to find the oxidation number/state of each sulfur atom.

Anyway, it looks like this:

[Schrödinger]

 

You don't need the structure in order to find the oxidation number/state of each sulfur atom.

Anyway, it looks like this:

You do need the structure to find the oxidation number/state of each sulfur atom.
Without the structure, you would be calculating average oxidation state of all sulphur atoms put together.

For instance, in this structure, the 2 S-atoms in the center have 0 oxidation state, while those at the ends have +5 state.
But without the structure, one would say that the oxidation state on each sulphur atom is +10/4 = +5/2

[UG]

Sorry, my brain was on thrid gear