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Topic: Hess's law LAB  (Read 4588 times)

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Offline matt1234

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Hess's law LAB
« on: December 15, 2009, 05:29:50 PM »
Hello,
Have a quick question with regards to a lab that was done.  With the formula Q = mc delta t.  Can 2 masses and specific heat capacities simply be added together in this equation?

Example:

Mass of a flask = 100 g
mass od water in the flask = 50 g

Specific heat capacity of the flask = 1 j/g*K
Specific heat capacity of water = 4.2 j/g*K

Can i perform the following calculation like this:

mTotal = 100g +50g
cTotal = 1 j/g*K + 4.2 j/g*K

Then Q = mTotal * cTotal * delta t

Is this the correct method of doing that calculation?

Offline matt1234

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Re: Hess's law LAB
« Reply #1 on: December 15, 2009, 06:49:16 PM »
Sorry i think i can make this more clear:

Would it be correct to do this:

Q = ( mflask + m Soln) * (Cflask + Csoln) * delta T

Offline savy2020

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Re: Hess's law LAB
« Reply #2 on: December 16, 2009, 02:30:24 AM »
Q = mTotal * cTotal * delta t
Is this the correct method of doing that calculation?
It is incorrect.
Because heat gained by water is mwCw :delta: T and that by flask is mfCf  :delta: T. So you add heat gained by both to get total heat
Now I think you could write the final expression ;)
:-) SKS

Offline matt1234

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Re: Hess's law LAB
« Reply #3 on: December 16, 2009, 07:42:19 AM »
Thank you.

Its Q flask + Q water = Q total

[m(flask) * c(flask) * delta T] + [m(soln) * c(soln) * delta T] = Qt



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