Oy
Sulfuric acid does not have to contain water. The pure liquid simply would not conduct electricity significantly in an analogous manner to how pure water with no electrolyte has too high of a resistance for electrolysis. That is not to say electrolysis needs water either, non-aqueous solvents can solvate compounds to their ions allowing conductivity and electrolysis, however the standard reduction potential tables become rather useless here as they are defined to be at a certain aqueous concentration (either 0.1 or 1M, I forget which). The addition of some other acid to conc. sulfuric would allow ion formation via acid-base chemistry, and electrolysis would then be possible. But this would have some really funky chemistry to it, and I am sure someone has tried some experiments regarding this, but I am not familiar with any literature in the field. Adding say BF3 or anhydrous nitric acid to conc. sulfuric acid would definitely allow some electrolysis to occur, but I would not want to be the one to have to predict the electrolysis products
Now onto sulfurous acid, which to the best of my knowledge is simply aqueous SO2, wiki says it is only known in the gas phase but I have a redox table in front of me having aqueous sulfurous acid, but that may be the same as aq. SO2.
S2O6 (2-) + 4H+ +2e- --> 2H2SO3 0.564 V
H2SO3 +4H+ + 4e- ---> S + 3 H2O 0.449 V
SO4(2-) + 4H+ + 2e- --> H2SO3 +H2O 0.172V
2H2SO3 + H+ + 2e- --> HS2O4- + 2H2O -0.056V
Furthermore, SO3 (sulfur trioxide, not to be confused with sulfite, SO3(2-) ) is reactive with water, producing sulfuric acid. We would encounter similar issues with reduction potentials, (if it is possible to oxidize sulfite to sulfur trioxide...) to that when one wonders why the electrolysis of aq. NaCl does not produce sodium metal.
So looking at a redox table, where the strongest oxidizing agent present is sulfurous acid, and the strongest reducing agent present is also sulfurous acid
The redox potentials indicate sulfurous acid would spontaneously react with itself, which in my limited experience usually means that one or more of these potentials was measured in reverse, and the half reaction only really works on one direction... but simply based on these potentials it would SEEM that electrolysis of sulfurous acid will produce sulfate and sulfur. There is the chance I missed an important reduction potential in my table, it is 20 pages long, in descending reduction potential, so I could have easily missed a value. Or there could be overpotential effects making the reaction take another pathway. In any case, the electrolytic disporportionation of sulfurous acid to sulfate and sulfur makes chemical sense, but if you want to be sure, grab some sodium sulfite and some sulfuric acid, mix in low concentrations so you do not gas yourself with SO2 too badly and electrolyse with graphite or Pt or Au electrodes and look for sulfur and then test for sulfate. If you get bubbles at either electrode, something other than what I predicted is occurring, and once you identify the gasses you can make a guess at what half reactions are occurring. Like I said, half reactions cannot predict everything. Experiment always trumps theory.
Now as for why sulfuric acid in water vs NaCl in water gives different products. With sulfuric acid the strongest oxidizing agent and strongest reducing agent present is both water. The acid and sulfate are merely helping increase conductivity.
With NaCl, just based on reduction potentials one would think that we would end up in the same boat as with sulfuric, after all chloride oxidation is less favorable than water oxidation based solely on reduction potentials, however there is an overpotential for the water oxidation (
http://en.wikipedia.org/wiki/Overpotential) compared to chloride oxidation, so chloride oxidation actually takes place.