[Lillys96]

So i've been racking my brains out at this question lately and i just can't seem to find the answer

25cm3 of HCl was neutralised with 25cm3 of NaOH.
Equation: HCl + NaOH ---- NaCl + H2O

i) the solution went from 12oC (degrees celcius) to 19.5oC and the specific heat capacity of the solution was 4.18J/gmol-1. Calculate the enthalpy change.
i did this bit this way
 since the 25cm3 of HCl was neutalised with 25cm3 of NaOH,i added the 2 together to get 50cm3.
so the energy change i got as 50 x 4.18 x 7.5= 1567.5J

ii)what have you assumed in this calculation?
DON'T KNOW THE ANSWER TO THIS ONE  

iii) If there were 0.025 moles of HCl neutralised,calculate the enthalpy change of neutralisation.
 

please help....i will totally appreciate it  

[Borek]

ii)what have you assumed in this calculation?
DON'T KNOW THE ANSWER TO THIS ONE  

How do you know what was heat capacity of teh solution?

iii) If there were 0.025 moles of HCl neutralised,calculate the enthalpy change of neutralisation.

I suppose they ask for MOLAR enthalpy.