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Topic: How many moles of N2O5 will remain after 6.6mins?  (Read 10431 times)

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Offline Craftylikeafly

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How many moles of N2O5 will remain after 6.6mins?
« on: February 06, 2010, 06:31:05 PM »
can someone tell what are the first steps in finding the moles?
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Offline jjkwest1

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Re: How many moles of N2O5 will remain after 6.6mins?
« Reply #1 on: February 06, 2010, 11:50:34 PM »
Find the molarity (mol/L) for N2O5, this will be your initial concentration, and then use the integrated first order rate law to find the concentration after 6.6 mins.
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Offline Craftylikeafly

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Re: How many moles of N2O5 will remain after 6.6mins?
« Reply #2 on: February 07, 2010, 10:17:05 AM »
okay i got .009 molarity N2O5, k= 6.82*10-3 and 6.6 mins

t1/2=.693/k

im having trouble understanding how i get moles using this
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Offline jjkwest1

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Re: How many moles of N2O5 will remain after 6.6mins?
« Reply #3 on: February 07, 2010, 05:48:28 PM »
use

Ln[N2O5]= -kt+ Ln[N2O5]0

convert 6.6 minutes to seconds and plug it in and you'll get the concentration of N2O5 at that time. Then you can get moles from there.
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Offline Craftylikeafly

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Re: How many moles of N2O5 will remain after 6.6mins?
« Reply #4 on: February 08, 2010, 02:19:15 PM »
now i got

-(6.82*10-3)(396sec)+ln(2.02*10-2/2.2L)=-7.41

then e-7.41=6.05*10-4M

then i use the 2.2 and multiply it by 6.05*10-4,to get mols right?
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