i always learned from HS and beyond was that Chlorine went first because it was in the right most column and is not inert.
You can't compare them directly - that could be done if both will undergo identical electrode reaction, that's not the case.
2Cl
- -> Cl
2 + 2e
- (E
0 = 1.359V)
could be directly compared with (non existing!)
2O
- -> O
2 + 2e
-but the real reaction is something different, like
2H
2O -> O
2 + 4H
+ + 4e
- (E
0 = 1.23V)
As you see oxygen evolves at lower potential, so it should appear first, even if the difference is not large.
That's only first approximation, as potential of water oxidation depends on the pH (four H
+ being produced), so the real potential in neutral solution will differ. However, standard potential is given for a solution containing 1 mol/L H
+, as concentration of H
+ (which is a product) is much lower in neutral solution, we should expect much lower potential at which oxygen will evolve (this is in a way similar to Le Chatelier's principle). If my calculations are correct (I am not claiming they are, I just hope
), formal potential for the oxygen evolution should be given by
E = 1.23 + RT/4F ln(p
O2[H
+]
4) = 1.22 - 0.059 pH
(assuming p
O2 of 0.21 atm, hence 1.22 instead of 1.23)
For neutral solution that gives 0.81V, way below potential at each chlorine evolves.
To be precise we should also do similar calculations for potential of Cl
-/Cl
2 reaction, but it won't change the situation. Potential doesn't differ much from 1.359V - it changes by 0.059V for each tenfold dilution of chlorides and we are using most likely solutions with concentrations between 0.01M and 3M (which is close to saturation).
As I wrote before, this is not entire truth yet, as depending on electrode material and overpotentials gas evolution may occur at even different potentials then those calculated.
Then, I can be completely wrong, that won't be for the first time