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Topic: calculating frequency factor  (Read 9226 times)

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Offline jjkwest1

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calculating frequency factor
« on: February 07, 2010, 12:08:39 AM »
The rate constant k for the reaction shown below is 2.6 * 10–8 L/mol * s when the reaction proceeds at 300.0 K. The activation energy is 98000 J/mol. (The universal gas constant (R) is 8.314 J/mol * K)
         2NOCl -> 2NO + Cl2
   Determine the magnitude of the frequency factor for the reaction.
   a)   1.2 *10^-8
   b)   4.6 *10^-9
   c)   3.2 *10^-9
   d)   2.7 *10^-8
   e)   9.1 *10^-9

I'm pretty sure that you use the equation k=Ae^(-Ea/RT)

Solving for A i got A= k/ (e^(-Ea/RT) = 2.6 * 10–8 /(e^(-98000/(8.314*300)) = 3.01235 * 10^9

however, this doesnt match with any of the above choices. Am i doing this the wrong way?

Offline jjkwest1

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Re: calculating frequency factor
« Reply #1 on: February 07, 2010, 05:44:55 PM »
please help....thanks  :)

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