[lisabella3686]

Hello Everyone,

can anyone tell me where to start on this question?  I don't have the foggiest idea even where to begin.

2.13x10^9L of rain falls. If the density of rain is 1.00g/cm3
How much heat is released when rain condenses from vapor to rain?

I am guessing that I will need to use the heat of vaporization of water, but I'm not sure how to relate g/cm3 to L and how knowing that will lead me to the answer

thanx for your time

[xiankai]

for water, its constantly known that 1g = 1mL.

your theory is correct, u have the heat of vapourisation of water right?

[lisabella3686]

yes, the dHvap = 40.7kJ
and the reverse of that reaction would make dHcond.= -40.7 kJ....correct?

So then, I have density, volume, dHcond.  I can find the grams from the density x volume. From grams I can find moles. And then I multiply the moles by the -40.7kJ?
p.s. you need to look up "LLama song" on google

[lemonoman]

Sounds like a good method to me.

P.S. Here's a llama, there's a llama
Slay it, that's what's right.
That song is so annoying that
I will not sleep tonight.

[xiankai]

actually u're only asked to find the heat released, not the latent heat of the water. just making sure u dont actually give a negative answer.