From the slope of the line and the stoichiometry of the reactions involved, calculate for each run the rate of reaction of (NH4)2S2O8 in moles/sec. Using these values and the avg volume of the reaction mixture during the run 50.00ml, determine for each run the rate of reaction of (NH4)2S2O8 in mole/litre/sec
For calculating the reaction rate in moles/sec do I need any fancy equations to do so? Like rate = k[A] that formula?
I'm not sure what the question is saying when it says from the slope of the line and stoichiometry of the reactions involved, for example what if the slope was 1.15x10^-5 what do I do from there? Here is a set of data from my first run
Time Moles consumed
50s 0.002
163s 0.004
250s 0.006
390s 0.008
487s 0.01