L=0.6 m, D=0.12 m of packed bed reactor
Height of packing material = 0.36 m
Volume of packed material = 3.14/4 * 0.12 * 0.12 * 0.36 = 0.00407 m3
Density of packed material = 690 Kg/m3
Mass of charcoal required = 0.0407 * 690 = 2.8 Kg
Hydraulic Retention Time = 4.07 L/h = 407 mL/h = 9.8 L/d
Can someone check if the calculations are right.