This problem is killing me.
What mass of NaOH(s) must be added to 1.0 L of 0.050
M NH
3 to ensure that the percent ionization of NH
3 is no greater than 0.0010%? Assume no volume change on addition of NaOH.
First, I wrote out NH
3 + H
2O
OH
- + NH
4+ and set up an ICE table. Then I realized that I had to figure out how NaOH would affect the system. I know Na
+ wouldn't do anything, and OH
- would shift the equilibrium to the left. I thought I could use LeChâtelier's principle, but that wouldn't tell me how much the equilibrium would shift. I have no idea where to go from here. Can someone please help me?