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Topic: complexing reaction  (Read 4954 times)

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Offline flacon

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complexing reaction
« on: March 20, 2010, 01:36:32 PM »
Hi, please can somebody help me? I can not solve this example:
What will be the molar concentration of ions Ni2+ in solution, which was prepared by mixing 100 ml 0,1 M Ni2+ and 150 ml 0,2 M EDTA? log β (NiY)=18,6, consider, α(Y4-) (H)=1

The redult is 1,26*10-19 M

Thank you for your help

Offline Borek

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Re: complexing reaction
« Reply #1 on: March 20, 2010, 01:40:34 PM »
Can you write reaction equation?

Can you write equation for stability constant?

Where does equilibrium lie? Far to the right? Far to the left? Somewhere in the middle?

Does this information help in finding - or at least approximating - concentrations?
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Offline flacon

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Re: complexing reaction
« Reply #2 on: March 20, 2010, 01:55:41 PM »
so I try to write reacton equation, but I'm not sure of it: EDTA= H4Y   H4Y + Ni2+ = NiH2Y + 2H+

β= [NiH2Y]*[H+]2/[H4Y]*[Ni2+]

but now I do not know what I can do next, please I need more help

Offline Borek

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Re: complexing reaction
« Reply #3 on: March 20, 2010, 04:19:14 PM »
My understanding is that you should ignore H+ and H4Y dissociation.

Instead of stating for the third time that you don't know, try to answer my questions.
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Offline flacon

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Re: complexing reaction
« Reply #4 on: March 20, 2010, 05:44:55 PM »
I really do not know how to solve it  :'(, please could you reveal me the solution and explain this examlpe to me, please

Offline flacon

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Re: complexing reaction
« Reply #5 on: March 21, 2010, 07:49:16 AM »
good I try answer your questions

The reaction equation is H4Y + Ni2+ = NiH2Y + 2H+  EDTA= H4Y

The equation for stability constant is β= [NiH2Y]*[H+]2/[H4Y]*[Ni2+]

The equilibrium is in the middle, because this is a equilibrium reaction

but it does not help me to solve this example :'(, please help me, I am desperate,  c´mon Borek please

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