I took the initial ph of the acid when no NaOH has been added yet (2.09) and 10^(-2.09) = ph and got 0.0081M is that right?
You have not listed informatin that you have, so nobody will be able to help. One thing is clear - this is wrong. If this is a strong acid - it is diprotic, so its concentration is different from what you have calculated. If it is a weak acid - it is not fully dissociated, so its concentration is different from what you have calculated.
You wrote something about adding NaOH. So perhaps that's just a titration question.