[taishar]

First off, let me thank anyone for the help. This is actually a problem for something I am having at work, but I can't find any good information on it. Your help is very much appreciated!

Ok, I am trying to get 30% (w/w) Hydrogen Peroxide. I am testing it against 0.1000N Potassium Permanganate in the ACS manual suggested manner. I know that 1 ml of KMnO4 = 1.701mg of H202.

Let us say that I weighed up 1.0000 grams of H202 in a beaker, added water, how would I figure this out? If someone could point me to the right formula then I should be able to get the rest of it


Thank you again!

[sjb]

What is the balanced equation for the reaction you are carrying out?

[taishar]

I believe this is correct as the formula?

% H2O2 (by weight) = [(mLs KMnO4) x (N) x (0.01701) x (1000)] / (grams of H2O2 sample used) where: N = Normality of the standardized potassium permanganate

I thought that was (w/v) though?

The balanced equation should be:

2 KMnO4 + H2O2 + 3H2SO4 ---> O2 + MnSO4 + K2SO4 + 4H20

[sjb]

Where has the 0.01701 come from?

[Borek]

I know that 1 ml of KMnO4 = 1.701mg of H202.

So after titration you can easily calculate mass of hydrogen peroxide in the sample, don't you?

Let us say that I weighed up 1.0000 grams of H202 in a beaker, added water, how would I figure this out?

Now you should titrate and use titre volume to calculate mass of hydrogen peroxide, then use definition of mass percentage.

[taishar]

0.01701 — Weight of sulfuric acid which is equivalent to 1 ml of
sodium hydroxide VS (1 mol/L), g.

[taishar]

Thanks Borek, so

% H2O2 (by weight) = [(mLs KMnO4) x (N) x (0.01701) x (1000)] / (grams of H2O2 sample used) where: N = Normality of the standardized potassium permanganate
 is the correct formula afterall!

Thank you both!