From the lab, I'm finding some particular challenges:
10ml of pure ethylendiamine (8.99g based on density) in 25mL water + 5mL of 10M HCl, + 8.03g of CoSO4.7H2O dissolved in 25mL, then air is passed through.
12(en) + 4HCl(aq) + 4CoSO4.7H2O(aq) + O2(g) -> 4[Co(en)3]ClSO4(aq) + 30H2O(l)
(en) = C2H8N2
This means CoSO4.7H2O is limiting, and the product 4[Co(en)3]ClSO4(aq) formed is 0.02857 mol - 10.59g.
I'm asked to find the percent yield, but the product was never measured. Do I assume the theoretical yield=actual yield, so 100% yield? Do I write ('percent yield not measured'?)
This affects the next reaction:
We added Barium L-tartrate to the solution, to precipitate BaSO4, and slowly crystallise (+)[Co(en)3](+)tartrateCl.5H2O.
That equation I think, is:
[Co(en)3]ClSO4(aq) + Ba(L-tart)(aq) + 5H2O -> BaSO4(s) + [Co(en)3]tart.Cl.5H2O(s)
So if my equations are correct, how am I supposed to get the percent yield of the
final product [Co(en)3]tart.Cl.5H2O(s)? Is the amount of reagent [Co(en)3]ClSO4(aq) presumed to be equal to it's theoretical yield? (ie 10.59g)?
I've been at this for many many hours, any help would be much appreciated,
Thanks