Hi, I hope someone can be of help. I'm confused about this question and hope someone can shed some light on it... Or me. Thanks!
Which of the following listed below will shift the equilibrium to the LEFT for the following reversible reaction?
SrCO3(s) <----> Sr2+(aq) + CO32-(aq)
a) decrease Sr2+
b) increase CO32-
c) add solid SrCO3
d) add solid NaNO3
e) all of the above