[pfnm]

Hi

CuCl2.4H2O(s)     ---->>   CuCl2(s)   +       4H2O(g)


Is this a ligand substitution reaction? Can CuCl2.4H2O be represented as tetraaquacopper(II) [Cu(H2O)4Cl2]? Or where are the Cl ligands and the H2O ligands in the complex? Does the complex form even when the crystals are actually solid?

Is the heating of CoCl2.6H2O (until colour change) a ligand substitution reaction? What of the heating of NiCl2.6H2O (again until colour change)? How are these represented in equation form?

Also:

[Fe(H2O)6+]3+     +          [Fe(CN)4]3- -------->

What does this form?

I know the Fe2+ will form Turnbull's blue with the 3- cyano complex, and Fe2+ with 4- cyano complex forms Prussian Blue.

What does the hexaaquairon(III) complex form with the hexacyanoferrate(III)? Does the Fe3+ complex donate a proton to water to form [Fe(H2O)5(OH)]2+, and then react to form Turnbull's Blue?

Does [Fe(H2O)6+]3+ on addition of H2O form [Fe(H2O)5(OH)]2+, then go back to the original form on addition of Excess H2O?


Also, why is (Cu(en)2]2+ unreactive with I- ions? Where can I find reduction potential of [Cu(en)2]2+?

Thank you.

[kimyacı]

 No this is not a substution reaction and it can be representes as [Cu(H2O)4Cl2].Cl ions are there for neutarilze the complex,that is complex is neutral. when heating of CoCl2.6H2O,ıt loses water and this isnt also substution reaction.when you study coordination chemistry from your book,you can find answers of your other questions.