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If 22.5 mL of 1.4x10-4 M HI is added to 28.0 mL of 4.4x10-3 M HI, what is the pH of the solution?Do I solve it this way?1.4x10-4+4.4x10-3= 4.54x10-3 M HI22.5mL+28.0mL=50.5mL=.0505L4.54x10-3/.0505=0.089901pH=log(0.089901)=1.05Is that correct?