Thanks,
I think I am going to work that out knowing quantitatively what's inside the solution... Although Cl
2 would be a nice way to understand the observed reactions -as Cl
2 could indeed oxidize easily Mn
2+ along with O
2-, by quickly looking at the electrochemical potentials, it sounds odd that O
2 would react with HCl to give Cl
2O
2 + 4H
+ + 4e
2H
2O E
0=1.23V
4Cl
- 2Cl
2 + 4e E
0=-1.36V
the overall reaction gives a negative potential, meaning the reaction should go the other way round.
Now you say that a simple way to generate Cl
2 gas is to add HCl to MnO
2 and that is done in classrooms as I read it. But looking at the potentials, we have the same
a priori. Meaning the reaction:
MnO
2(s)+4HCl(aq)
Cl
2(g)+MnCl
2(aq)+H
2O(l) has a :delta:(E
0) negative.
Coming from the following half reactions:
Cl
2(g) + 2 e
2 Cl
− E
0=+1.36
MnO
2(s) + 4 H
+ + 2 e
Mn
2+ + 2 H
2O E
0=+1.23
So I guess it may be a matter of concentrations... Or am I missing something?