OK so far i know the equation for part two D=[(wo-w1)/y]/w1/x
with x=1 y=0.05 and wo=? and w1=?
To sum up: this is ok, though seems to me you've inverted the volumes: x should be 0.05 L and y 1 L, I think...
Now, w
0 and w
1 are the concentrations (the first is the starting one, the second tells us the amount of compund extracted and it's 6µg/L)
If you do the same thing only with the second extraction (which gives us a w
2 of 0.5µg/L) you'll find another equation and you'll be able to set up a two-equation system to find out D and w
0, the answers for the first two points of the exercise.
Try this and then we'll think about the third one: you can't do the third without having understood the other two.