[citron2k1]

So far i have 2Sc + O2 -------> Sc2O3. Please help.

[sjb]

So far i have 2Sc + O2 -------> Sc2O3. Please help.

Maybe it will be easier with half equations? What is the oxidation state of Sc on the left and right? Of the oxygen?

[Borek]

I think it is too easy problem from oxidation states - and judging from the fact it is just half of September OP most likely has no idea how to balance simple equation, oxidation states will just add to confusion.

Citron, what do you know about equation balancing?

[citron2k1]

I always have problems balancing equations. I am confused by that fact that there are 3 oxygens on the product side.

2Sc + O2 ------> Sc2O3

O2 has to be on the reactant side because it's a diatomic correct? So if I put 1.5 oxygen on the reactant side, I would have to multiply the whole equation by 2 correct? So the end result would be:

4Sc + 3O2 --------> 2Sc2O3

That changes the whole product. I dunno what I'm doing.

[Borek]

I always have problems balancing equations. I am confused by that fact that there are 3 oxygens on the product side.

2Sc + O2 ------> Sc2O3

O2 has to be on the reactant side because it's a diatomic correct? So if I put 1.5 oxygen on the reactant side, I would have to multiply the whole equation by 2 correct? So the end result would be:

4Sc + 3O2 --------> 2Sc2O3

That's the correct approach and the correct answer.

That changes the whole product. I dunno what I'm doing.

No, it didn't change the product - it changed amount of product. Sc₂O₃ means one molecules (or one mole) of scandium oxide, 2Sc₂O₃ means two molecules (or two moles) of the same scandium oxide.

[citron2k1]

Thanks for that clarification Borek. Finally I'm on the right track.