Hello, thanks for looking at my questions.
Legend : e = exposing
Question 1:
What is the mass (in gram) of benzene (C6H6) which contains 7.74 x 10 e24 atoms of hydrogen?
First I took the atomic mass of Hydrogen (1.007) and multiplied it by 6 which gave me 6.042. Then I used the law of avogadro to divide it : 6.042 divided by 6.022045 x 10 e23, which then gave me 1.003313658 e 23, then I finally multiplied it by 77.2 to give me the answer I was looking for (7.74 x 10 e24 atoms of hydrogen).
Subsequently, I assumed since it was C6, Carbon (12.01) would have to be multiplied by 6 to join its comrade hydrogen with an atomic mass of 72.06.
Fused they would give me 78.102 which I would then multiply by 77.2 to give me the mass of the benzene in grams = 6029.9 grams in relation to the many atoms of hydrogen.
Is this correct, what went wrong?
Question 2:
Calculate the number of hydrogen atoms (in mol) found in 27.5 mL of isopropyl (C3H8O) if the mass (volume) of isopropyl at a certain temperature consists of 0.825 g/mL.
I'm guessing H8(8.056) divided by 6.022 x 10 e23 = 1.33761541 x10 e23 multiplied by 0.825 = 1.10365371 x 10 e 23 multiplied by 0.2750 = 3.035046496 x 10e22
But where does the room temperature come in to play?
I have absolutely no clue how to calculate this, I didn't get a formula anywhere, an example would be nice. Please and thank you.
I missed the second class due to a late night lab, and look where I am today!!
All help is appreciated, thank you
(0.2750) (27.5) divided by 0.825 = 9.166 divided by 6.022 x 10 e 23 = my gobbledegook.