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Topic: cyclic compound and its equivalent protons for the H NMR signal  (Read 4219 times)

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Offline saint_john

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cyclic compound and its equivalent protons for the H NMR signal
« on: September 21, 2010, 03:12:22 PM »

I say that this molecule is not aromatic because both its A and B carbons are sp3. In order for the molecule to be aromatic it cannot have sp3 carbons because it must be planar. However i am not 100 % sure about this molecule's aromaticity.

Also, i'm trying to determine which protons are chemically equivalent on this molecule for its H NMR signal. I tried to determine this by using a horizontal plane to cut the molecule in half right between the A and B carbons.
However, the wedges confuse me about this.

Offline sjb

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Re: cyclic compound and its equivalent protons for the H NMR signal
« Reply #1 on: September 21, 2010, 05:49:04 PM »
(a picture of 3a,6a-dimethylbenzo(b)fluoranthene)



Re equivalences, what happens when you flip the system end over end, going towards you?

Offline orgopete

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Re: cyclic compound and its equivalent protons for the H NMR signal
« Reply #2 on: September 24, 2010, 08:16:16 AM »
Compare the resonance structures.
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