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Topic: Ag Electrolysing OH-  (Read 3462 times)

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Offline oneat

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Ag Electrolysing OH-
« on: September 30, 2010, 02:43:06 PM »
Will I get oxygen or Silver cation electrolysing water with silver cathode?

Offline DevaDevil

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Re: Ag Electrolysing OH-
« Reply #1 on: October 11, 2010, 06:05:32 AM »
reduction:

2H+ + 2 e---> H2 (g); E0 = 0V

Oxidation possibilities:

2 H2O -->  4 H+ + 4 e- + O2 (g);  E0 = -1.23V
ro
2Ag(s) + H2O --> Ag2O + 2 H+ + 2 e-;  E0 = -1.17V (partial oxidation of silver)
or
Ag (s) --> Ag+ + e-; E0 = -0.80V (full 1-valent oxidation of silver)


which one of the oxidation reactions costs the least energy based on the NERNST equation? This is the one that will happen in electrolysis.

Offline Borek

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Re: Ag Electrolysing OH-
« Reply #2 on: October 11, 2010, 06:17:50 AM »
which one of the oxidation reactions costs the least energy based on the NERNST equation? This is the one that will happen in electrolysis.

Unless it will be disfavored for kinetic reasons.
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Offline DevaDevil

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Re: Ag Electrolysing OH-
« Reply #3 on: October 11, 2010, 06:35:08 AM »
agreed, same goes if indeed the silver-oxide (or hydroxide) layer is formed to cover the electrode.

I just point to the way on how to predict if dissolution might happen

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