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Topic: Chem Lab  (Read 3681 times)

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Offline tanner.e

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Chem Lab
« on: October 06, 2010, 07:31:46 PM »
I did a chem lab today and I have a bunch of questions to see if I'm on the right track with the Lab report.

1. what is the balanced precipitation reaction that I was working with?   I used the products Na2CO3 , Co(NO3)2 , H20  and (CH3)2CO 

would the reaction be Na2CO3+Co(NO3)2+H2O + (CH3)2CO ----> ...  bit confused how to make the product but it made a solid while all the other substances were liquids.

2. How many moles of cobalt nitrate do you use for the reaction?

where I have the volume of 10 mL of Co(NO3)2  .   I did n= 10mL * 1 g Co(NO3)2/ 1 mL Co(NO3)2  * 1 mol Co(NO3)2 / 166.94 g Co(NO3)2  = 0.0599 moles which I dont think sounds right. Then do I multiply that by the avagedros number?

Thanks for any help

Offline Borek

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Re: Chem Lab
« Reply #1 on: October 07, 2010, 03:48:20 AM »
Please elaborate on the procedure. You have not listed enough information to let us try to help.
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Offline sjb

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Re: Chem Lab
« Reply #2 on: October 07, 2010, 12:46:39 PM »
I did a chem lab today and I have a bunch of questions to see if I'm on the right track with the Lab report.

1. what is the balanced precipitation reaction that I was working with?   I used the products Na2CO3 , Co(NO3)2 , H20  and (CH3)2CO 

would the reaction be Na2CO3+Co(NO3)2+H2O + (CH3)2CO ----> ...  bit confused how to make the product but it made a solid while all the other substances were liquids.

2. How many moles of cobalt nitrate do you use for the reaction?

where I have the volume of 10 mL of Co(NO3)2  .   I did n= 10mL * 1 g Co(NO3)2/ 1 mL Co(NO3)2  * 1 mol Co(NO3)2 / 166.94 g Co(NO3)2  = 0.0599 moles which I dont think sounds right. Then do I multiply that by the avagedros number?

Thanks for any help

Was the cobalt nitrate a solution, or is it really a liquid?

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