One mol of liquid occupies 22.4 L at STP, but I'm not sure what mol of gas would occupy.
Its actually one mole of gas which occupies 22.4L at STP.
Now I'm not 100% on how to answer this question but here it goes,
If you know that one mole = 22.4L you can find the amount of moles of each gas:
4.2/22.4=0.18750 <-- (moles of N
2)
6.3/22.4=0.28125 <-- (moles of O
2)
So as we know the ratio in the equation is 2N:3O we will have to divide the moles by their ratio so its 1:1 hence giving us the restricting reagent.
0.18750/2=0.9375
0.28125/3=0.9375
Therefore given your amounts of each gas there shouldn't be any excess of either