Assign oxidation numbers to all elements in ALL compounds.
Ok thanks, so...
On LHS 3Cl
2= 0 charge, O= (6)(-2)+ H =(6)(1) so -6 charge on LHS.
On RHS ClO
3- =Cl(+5) 3O(-6) = -1, and 5Cl(-1) = -5, and 3H
2O has neutral charge, 6H(+6) 3O(-6).
it seems that Cl has both gained 5 e and lost 5 e on the RHS please help