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Topic: Dissolving one mole of salt in water yields how many ions in complex ions  (Read 3381 times)

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Offline skibum143

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Dissolving one mole of salt in water yields five moles of ions in which of the following?

 A: NH4[Pt(NH3)Cl3]
 B: tris(ethylenediamine)cobalt(III) sulfate
 C: tetraaquadichloronickel(IV) chloride
 D: [Co(NH3)2(en)Cl2]Cl
 E: [Co(en)2Cl2]Br
 F: sodium hexacyanoferrate(II)
 None of these compounds

Do the ions outside the bracket count? If so, I see five in A. (NH4+, PT+2, 3Cl-) If not, I don't see any? I can't get this one right...

Offline Schrödinger

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Re: Dissolving one mole of salt in water yields how many ions in complex ions
« Reply #1 on: November 04, 2010, 10:22:13 PM »
All those inside the square bracket shouldn't be counted separately.

So, for the first one, the ions that are present in the solution are NH4 + and [Pt(NH3)Cl3]-.

So, now I believe you can go on and try the other ones :)
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