In the NMR spectra of ethyl iodide, the peaks for methyl hydrogens appear at 1.9 ppm and the peaks for methylene hydrogens appear at 3.2 ppm with j= 8 Hz the number of peaks given by the methyl hydrogen is __a__ with the approx area ratio __b__. These peaks are separated by__c__ Hz. The number of peaks given by the methylene group is __d__ with the approx ratio__e__ . These peaks are separated by__f__ Hz. The ratio of the total area of the methyl peaks is __g__. Of these two groups of peaks, the __h__ peaks are further down field. The chemical shift difference between these peaks of 1.3 ppm corresponds in a 60MHz instrument to __i__.
okay:
a 3
b 1:2:1
c. ?
d 4
e 1:3:3:1
f 8Hz
g 3:2
h methylene
i 1.6*60 = 78Hz
are any of this right, do you have suggestions for those that are not right? Thank you for you time.