December 23, 2024, 07:10:32 AM
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Topic: Help with some calculations regarding titration using iodine and sulfur dioxide  (Read 4187 times)

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Offline wala01

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Alright well, i'm doing an experiment that basically tests for the amount of sulfur dioxide in dried apricots. What i'm doing is blending the apricots and mixing it with water and titrating iodine into that solution. My problem is, i don't have much of the iodine needed for the experiment and i want to know if i need to order more iodine before i start.

Here is the data given to me to do the calculations: I tried it, but i'm not sure if this is correct or not. It would be great if you guys could help me out (:

So here are the half equations i came up with:

SO2 + 4H+ + 4e- -> S + 2H2O
2I- -> I2 + 2e-           
SO2 + 4H+ + 4I- -> S + 2I2 + 2H2O

It tells me that the maximum sulfur dioxide content of dried apricots is 3.000g of SO2 per kg of apricots. In 20g of apricots, this translates to .06g of SO2 in 20g of apricots.

Which is .000938 mols (mols = mass/molar mass.     mols = .06/64)
The mole ratio of SO2 to I2 is 1:2
So, 0.000938:0.001875.

The volume of I2 needed to reach an endpoint was then calculated to be 48mL... Is this correct?
V= n/C     C of I2 is 0.01g of iodine in each mL, which is .000039mol per mL
So V = 0.001875/.000039 = approx. 48mL.

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So here are the half equations i came up with:

SO2 + 4H+ + 4e- -> S + 2H2O
2I- -> I2 + 2e-           
SO2 + 4H+ + 4I- -> S + 2I2 + 2H2O

Huh?

You said you titrate with iodine, not with iodide.
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Offline wala01

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oh my bad... so... then i have

I2 + 2e-  :rarrow: 2I-
SO2  :rarrow: SO42- + 2e-   ?

With this i would get I2+SO2  :rarrow: 2I- +SO42-

Now the ratio between I2 and SO2 will only be 1:1?

And the final volume i would need will be approx 24mL

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With this i would get I2+SO2  :rarrow: 2I- +SO42-

This is not balanced yet. But ratio should not change after balancing.

And yes, around 24 mL per 0.06g of SO2.
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