Hi in the following electrochemical reaction Ag
+ + 2NH
3 Ag(NH
3)
2+The voltaic cell reaction was done twice . and the potentials measured were (a)E
cell= 0.07V and (b)E
cell= 0.10V .
I need to calculate the concentration of [Ag
+] at equilibrium in each reaction using the Nernst equation (and the E
cell)I cannot figure out how to arrange the equation to get this.
Other information I have is E
o =0.55 V and T= 292 K
PLEASE help.. I have spent hours trying to solve this.please