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Offline Boxxxed

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Relatively Simple Question
« on: January 10, 2011, 02:06:19 PM »
Ethane burns in air according to the following equation:  2C2H6 (g) + 7O2(g) → 4CO2 + 6H2O  What volume of O2 is required for complete reaction with 5.2 L of C2H6?  What volume of water vapour is produced?  Assume constant temperature and pressure.

How do I figure out the moles of C2H6 from the volume?

Offline JGK

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Re: Relatively Simple Question
« Reply #1 on: January 10, 2011, 02:16:18 PM »
What is the volume of 1 mole of gas at STP?

If you start from there, you should be able to work it out.
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Offline Boxxxed

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Re: Relatively Simple Question
« Reply #2 on: January 10, 2011, 04:01:18 PM »
This would be easy if I had the mass. I'm not sure how to get volume from pressure or volume?

Offline sjb

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Re: Relatively Simple Question
« Reply #3 on: January 10, 2011, 04:05:00 PM »
What does Avogadro's law state?

Offline Boxxxed

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Re: Relatively Simple Question
« Reply #4 on: January 10, 2011, 04:29:42 PM »
v/n=k

How is n derived from any of these formulas?

Offline sjb

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Re: Relatively Simple Question
« Reply #5 on: January 10, 2011, 04:45:54 PM »
v/n=k

How is n derived from any of these formulas?

Can you define your terms here? You could be right (as far as I know), but I'm not sure.

Offline Boxxxed

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Re: Relatively Simple Question
« Reply #6 on: January 10, 2011, 08:42:30 PM »
volume over n(moles)=constant(k)

It is now cleared up that it is an approximation. At first it made no sense since different molecules are of different sizes. I still don't know how to derive moles from volume. Do I just use standard temperatures and pressure? How is a formula rearranged accordingly?

Offline opti384

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Re: Relatively Simple Question
« Reply #7 on: January 10, 2011, 09:20:16 PM »
Do I just use standard temperatures and pressure?

Yes since the question does not give any specific temperature and pressure but states "assume constant temperature and pressure."

Offline sjb

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Re: Relatively Simple Question
« Reply #8 on: January 11, 2011, 02:20:28 AM »
volume over n(moles)=constant(k)

So what that's saying is that for a given number of moles of gas, the volume is independent of the identity of the gas. You don't need to know the mass here.

Offline Borek

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Re: Relatively Simple Question
« Reply #9 on: January 11, 2011, 05:08:31 AM »
volume over n(moles)=constant(k)

It is now cleared up that it is an approximation. At first it made no sense since different molecules are of different sizes. I still don't know how to derive moles from volume. Do I just use standard temperatures and pressure? How is a formula rearranged accordingly?

Actually it is a quite good approximation, as long as the gas behaves as an ideal one.

Question wants you to use the fact that if 1 moles of gas reacts with with 1 mole of other gas, their volume ratios are 1:1 as well.
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