I have a series of questions that build off of each other, and I have answered all of them but the final one incorrectly.
Question #1: If a volatile liquid is added to a sealed flask, the total pressure inside the flask is a sum of the air pressure and the vapor pressure of the liquid. Consider a flask at 298 K with an air pressure of 732. mmHg to which some n-butanol is added. If the measured pressure after the addition is 737. mmHg, what is the vapor pressure of n-butanol at 298 K?
Answer #1: 5mmHg
Question #2: Now, if the temperature inside the same flask is increased to 328 K the measured pressure will increase to read 849. mmHg. This is because both the air pressure and the vapor pressure of n-butanol will increase. The air pressure at 328 K can be calculated from its value at298 K by using Pi/Ti=Pf/Tf.
(a) What is the value of the air pressure at 328 K (in mmHg)?
Answer (a) 806 mmHg
(b) Using that last result and measure pressure at 328 K, what is the vapor pressure of n-butanol at 328 K?
I can't seem to figure out the formula for this. I don't want the answer, I just would like to be explained on HOW to find the answer.