[aria152]

I have been given a set of pressures in bar and their corresponding molar volumes for Hydrogen gas. I have to calculate the 2nd virial coefficient of hydroen at 0 degrees.  
Anybody have any suggestions on how to do it ??
I think  that I am supposed to plot the given values and the grdient is supposed to give me "B" but I do not know how to go about it..
 
 PLease *delete me*!  

[BAL]

Hello Aria, i dont think to be very helpfull but you can find it in any physical chemistry textbook, you can exprese the B like a function on term of  a Vander-waalls, Dieterichi, constants. jus remember that PV/TR=1=AT+BT2+CT3..., I don't know if the last expresion is correct, I have my book far far away form here, that can give you and idea what I am saying.
Please look for PhysicalChemistry text Book, Atkins or Castellan, yuo will find more information, and tri to calculate A and C is a like a funtion of a Vander Waalls Gas, is a good exercise!

Good Luck!

[GCT]

I have been given a set of pressures in bar and their corresponding molar volumes for Hydrogen gas. I have to calculate the 2nd virial coefficient of hydroen at 0 degrees.  
Anybody have any suggestions on how to do it ??
I think  that I am supposed to plot the given values and the grdient is supposed to give me "B" but I do not know how to go about it..
 
 PLease *delete me*!  

it's P=(RT/Vm)(1+ B/Vm+C/Vm^2....), you have the temperature, if you know the corresponding molar volume and pressure, you should easily be able to solve for P...watch out for the units!!!

[gregpawin]

You can use excel... it has a polynomial fitting... just plot the pressure divided by RT versus the inverse molar volume.... someone please correct me because i haven't done this one before.  then one of the coefficients of the polynomial terms is your virial coefficient

[mhill37]

There are also several convenient mathematical tools posted here:

http://www.akiti.ca/Mathfxns.html

For example, it includes a utility for solving a Cubic Equation and one for Data Fitting.

Regards,


Michael

[aria152]

thanks guys.. that was really helpful..