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Topic: Acid Hydrolysis of Esters  (Read 5348 times)

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Offline arooga

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Acid Hydrolysis of Esters
« on: February 02, 2011, 06:32:47 PM »
How many mmol of HCl would be required at the minimum to completely hydrolyze 2 mmol of methyl acetate?

I know for base-catalyzed hydrolysis of esters, each mole of ester hydrolyzed requires 1 mole of base.

According to the mechanism of acid-catalyzed hydrolysis of esters from this source, http://www.mhhe.com/physsci/chemistry/carey/student/olc/graphics/carey04oc/ref/ch20reactionsesters.html, is it safe to conclude that 2 moles of acid are required to hydrolyze each mole of ester?

Thank you
« Last Edit: February 02, 2011, 06:44:34 PM by arooga »

Offline Dan

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Re: Acid Hydrolysis of Esters
« Reply #1 on: February 03, 2011, 04:28:26 PM »
is it safe to conclude that 2 moles of acid are required to hydrolyze each mole of ester?

I'm afraid not. Can you explain how you came to this conclusion? Start with the absolute basics:

MeCOOMe + -OH ---> ?

and

MeCOOMe + H3O+ ---> ?

and reconsider the problem.
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Offline Arene

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Re: Acid Hydrolysis of Esters
« Reply #2 on: February 03, 2011, 04:42:41 PM »
The mechanism uses two moles of acid to catalyze the reaction I believe.

Offline Dan

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Re: Acid Hydrolysis of Esters
« Reply #3 on: February 03, 2011, 04:48:56 PM »
The mechanism uses two moles of acid to catalyze the reaction I believe.

You miss the point as well.

Complete the balanced equations I started. It is not actually necessary to know the mechanism is AAC2 to answer the question - acid/base equilibria is the key. I think it's a bad question actually.
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Offline Arene

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Re: Acid Hydrolysis of Esters
« Reply #4 on: February 03, 2011, 04:58:18 PM »
I guess I do. I would love to learn.

MeCOOMe + OH-  ---> MeCOO + MeOH

MeCOOMe + 2H3O+ --> MeCOOH + MeOH + H3O+


Offline Arene

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Re: Acid Hydrolysis of Esters
« Reply #5 on: February 03, 2011, 05:00:05 PM »
It looks like it is catalyzed by two hydronium, yet mechanistically one returns to solution. Is this reflected properly in the equations above?

Offline Dan

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Re: Acid Hydrolysis of Esters
« Reply #6 on: February 03, 2011, 05:08:31 PM »
Ok, careful with your balancing.

I guess I do. I would love to learn.

MeCOOMe + 2OH-  ---> MeCOOH + MeOH + OH-

This is not balanced (charges are 2- on the left and 1- on the right) - to make life easier, two hydroxides are not necessary.

Quote
MeCOOMe + 2H3O+ --> MeCOOH + MeOH + H3O+

Again, not balanced (charges) - two hydroniums are not required
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Offline Arene

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Re: Acid Hydrolysis of Esters
« Reply #7 on: February 03, 2011, 05:28:52 PM »
thank you. I completely ignored the charges.

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