[mol]

1.how is the molarity inversely proportional to degree of dissociation 'i' ?
 2.also, how to realte that 20% of dissociation equals to 1.2 in a Van't Hoff factor?

pls include if there are any steps involved here...
pls help

[DevaDevil]

1. Reason this out for me please: If I increase the concentration of a dissociating compound (for example copper sulfate) in water, then .

2. About the van 't Hoff factor: For most ionic compounds dissolved in water, the van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance. (in case of ideal solutions)
Which means that for example NaCl, fully dissociated, will have van 't Hoff factor of 2 (because 2 ions are formed out of the NaCl; Na⁺ and Cl^-)
Now you reason this factor of 1.2 through.

[mol]

yes that makes clear. thank you Devadevil