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Topic: Partial Pressures: 2SO2(g) + O2(g) --> 2SO3(g)  (Read 9789 times)

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alimarie

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Partial Pressures: 2SO2(g) + O2(g) --> 2SO3(g)
« on: September 09, 2005, 04:57:46 PM »
I need help on this problem. I have no idea how to solve it! Please reply A.S.A.P. it's due in a few hours.  ???

Consider the reaction:
2SO2(g) + O2(g) --> 2SO3(g) at constant temperature. Initially a container is filled with pure SO3(g) at a pressure of 2 atm, after which equilibrium is allowed to be reached. If y is the partial pressure of O2 at equilibrium, the value of Kp is:

 A.
(2 - 2y)2
-------
(y2)(2y)

 B.
(2 - y)2
-------
(y2)(y/2)

 C.
(2 - y)2
-------
(2y)2(y)

 D.
(2 -2y)2
-------
(2y)2(y)

 E. none of these
« Last Edit: September 17, 2005, 02:31:06 AM by Mitch »

Offline Borek

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Re:Partial Pressures *delete me*
« Reply #1 on: September 09, 2005, 06:29:28 PM »
First, write down expression for Kp.

Second, write down equilibrium amounts of all substances. You know what was initial pressure of SO3, all pressures can be calculated using something like ICE table.

Finally, substitute.
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alimarie

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Re:Partial Pressures *delete me*
« Reply #2 on: September 09, 2005, 07:02:48 PM »
I don't know what to se for Kp, can you guide me exactly what to do pleasE?

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