[lsc04361]

I know how to derive integrated rate law from differentiated rate law.

However, the integrated rate law present always take the example of
                                 R -> P (where R is the reactant and P is the product)
How about those reaction
                                2R -> P
Do the integrated law change correspondingly or just the same one??


In my opinion, it should be different since the rate k(take zeroth order as example)
                                        k = -1/2 d[R]/dt
instead of                         
                                        k = - d[R]/dt

I am not sure about this because lots of place in the internet or the textbook presenting only the [R]=[R]o - kt(zeroth order as example).

Thanks.