[al526]

How many liters of carbon dioxide gas are produced from the complete combustion of 24.0 liters of C2H2 if all gases are measured at 50°C and 101.3 kPa?

I got the answer as 56.8 L, but apparently it's wrong. I don't know if there's been a mistake on the answer key, or if I did something wrong.

What I did:
2C2H2+ 5O2 = 4CO2+ 2H2O
24.0 L C2H2= 1.07 M
1.07M * 2= 2.14 M CO2

V=nRT/P=2.14M(0.0821)(323.15K)/1atm= 56.8 L CO2


thanks!

[opti384]

V=nRT/P=2.14M(0.0821)(323.15K)/1atm= 56.8 L CO2

Is the pressure really 1atm?

[DrCMS]

How many liters of carbon dioxide gas are produced from the complete combustion of 24.0 liters of C2H2 if all gases are measured at 50°C and 101.3 kPa?

I got the answer as 56.8 L, but apparently it's wrong. I don't know if there's been a mistake on the answer key, or if I did something wrong.

I do not know what the answer key says but i do know your answer is wrong.  If you read the question again properly you might get the right answer which does not require much maths at all.

[rabolisk]

I got the answer as 56.8 L, but apparently it's wrong. I don't know if there's been a mistake on the answer key, or if I did something wrong.

24.0 L C2H2= 1.07 M
1.07M * 2= 2.14 M CO2

V=nRT/P=2.14M(0.0821)(323.15K)/1atm= 56.8 L CO2

You did something wrong, namely the bolded parts.

[al526]

I got the answer as 56.8 L, but apparently it's wrong. I don't know if there's been a mistake on the answer key, or if I did something wrong.

24.0 L C2H2= 1.07 M
1.07M * 2= 2.14 M CO2

V=nRT/P=2.14M(0.0821)(323.15K)/1atm= 56.8 L CO2

You did something wrong, namely the bolded parts.

okay thanks~
so the conversion between kPa and atm is correct.
is the liter to mole conversion incorrect? (24 L / 22.414)? which would affect the number of moles of CO2...

[opti384]

The volume of 1 mol of gas will be 22.4L only at 1atm, 0°C.

[rabolisk]

I got the answer as 56.8 L, but apparently it's wrong. I don't know if there's been a mistake on the answer key, or if I did something wrong.

24.0 L C2H2= 1.07 M
1.07M * 2= 2.14 M CO2

V=nRT/P=2.14M(0.0821)(323.15K)/1atm= 56.8 L CO2

You did something wrong, namely the bolded parts.

okay thanks~
so the conversion between kPa and atm is correct.
is the liter to mole conversion incorrect? (24 L / 22.414)? which would affect the number of moles of CO2...

That is both incorrect and unnecessary.

V=nRT/P=2.14M(0.0821)(323.15K)/1atm= 56.8 L CO2

Is the pressure really 1atm?

The pressure is indeed 1 atm, and not the reason why he got the answer wrong..

[opti384]

The pressure is indeed 1 atm, and not the reason why he got the answer wrong..

Did you keep this "if all gases are measured at 50°C and 101.3 kPa" in mind?

[rabolisk]

The pressure is indeed 1 atm, and not the reason why he got the answer wrong..

Did you keep this "if all gases are measured at 50°C and 101.3 kPa" in mind?

I'm not sure exactly what you mean. I was just saying that 101.3 kPa = 1 atm, but that is irrelevant in solving this problem, because "all gases are measured at 50°C and 101.3 kPa".

[al526]

Wow, I see what I did wrong...such an obvious mistake.

I got the right answer.
Thanks so much for everyone's *delete me*!