[CLiz]

Could someone please advise if I have answered the question correctly?

Thanks!

Calculate the Ksp of Ag2CrO4. ..
Ksp measured under normal conditions is 25 degrees C

Ag2CrO4 ↔ 2Ag1+ + CrO4

        Ksp = [Ag1+]2 + [CrO42-]


ICE      Molar Solubility   [Ag1+] in mol/L   [CrO42-] in mol/L
Initial                     x
Change            +2x         +x
Equilibrium              2x          x

1.1   X 10-12 = [2x]2

1.1X 10-12 =4x3
1.1X10-12 /4 = x3
2.75X10-13= x3
3√2.75X10-13=x
6.5X10-5=x

The molar solubility of Ag2CrO4 is 6.5X10-5

[Borek]

Calculate the Ksp of Ag2CrO4. ..
Ksp measured under normal conditions is 25 degrees C

I have never seen Ksp expressed in degrees C, but if it is measured as 25, there is no need to calculate it. It is 25.

The molar solubility of Ag2CrO4 is 6.5X10-5

Interesting result, no idea how it is related to the question. Molar solubility is not Ksp (which is given as 25).

Sigh.

[CLiz]

lol i read the question COMPLETELY wrong, interesting enough though i read another thread regarding the same question and u responded to it

[Borek]

Probably the question there was worded in a more comprehensible way.