Here's a good video on how to find a limiting reagent.
http://www.youtube.com/watch?v=7e6KJKWI7JoBasically, what you want to do is find which reactant you won't have enough of. You can do this by using mole ratios for one of the reactants. Let's say you have for a equation (make sure it is balanced first) O
2+2H
2 -->2H
2O. You have 4 moles of oxygen and 16 moles of hydrogen. To find the limiting reagent, pick one of the reactants and write it down. Then, use a mole ratio with the other reactant on top and the reactant you picked earlier on the bottom. So, with the example I used (slash is the fraction line):
16 mol. H
2x1 mol O
2/2 mol H
2.
You will find that you need 8 mol of O
2 for the reaction to occur. Since you have less than what is needed, O
2 is the limiting reagent.
Hope this helps. The video I included should help as well.