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Topic: Investigation: determining limiting reagent  (Read 5157 times)

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Offline western0

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Investigation: determining limiting reagent
« on: March 17, 2011, 06:13:53 AM »
We need to conduct an experiment to determine the limiting reagent in each reaction, i am unsure how to do this.  The reactions are:

1. Solution of Barium nitrate and sulfuric acid

2. Solution of Barium nitrate and copper sulfate

I have no idea what i need to do to prove what the limiting reagent is in each equation. 

Any help would be appreciated,

thank you.

Offline AWK

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Offline Chrs_Rcc

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Re: Investigation: determining limiting reagent
« Reply #2 on: March 17, 2011, 05:00:23 PM »
Here's a good video on how to find a limiting reagent.

http://www.youtube.com/watch?v=7e6KJKWI7Jo

Basically, what you want to do is find which reactant you won't have enough of. You can do this by using mole ratios for one of the reactants. Let's say you have for a equation (make sure it is balanced first) O2+2H2 -->2H2O. You have 4 moles of oxygen and 16 moles of hydrogen. To find the limiting reagent, pick one of the reactants and write it down. Then, use a mole ratio with the other reactant on top and the reactant you picked earlier on the bottom. So, with the example I used (slash is the fraction line):

16 mol. H2x1 mol O2/2 mol H2.

You will find that you need 8 mol of O2 for the reaction to occur. Since you have less than what is needed, O2 is the limiting reagent.

Hope this helps. The video I included should help as well.

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