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Topic: Redox Titration Question  (Read 3352 times)

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Offline kimkim

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Redox Titration Question
« on: April 17, 2011, 03:25:31 AM »
25 mL of H2O2 solution is diluted to 0.5L
0.02L of this solution reacts with 0.02148L of 0.112M permanganate solution (MnO4-)aq
Find the molarity of the original hydrogen peroxide solution.

Okay, so I'm not sure what the products of this reaction will be. I need the products in order to balance the equation and therefore get the ratio between the reactants.
With the ratio of the reactants I can find the number of moles of the H2O2 and use c1xv1=c2xv2 to get the original M (c1)

With normal redox equation I think you balance them so the electrons on the products cancel out the reactants.

What are the half equations? I am confused because from what I can tell on my data sheet, the electrons for the reactants are both on the left side, and they both require energy to react.
Any help/advice is appreciated as we have not yet covered redox titrations in our course.

Offline Borek

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Re: Redox Titration Question
« Reply #1 on: April 17, 2011, 04:49:42 AM »
H2O2 is oxidized to O2.

use c1xv1=c2xv2 to get the original M (c1)

This equation you can use right now - but it is not correct, as it doesn't take stoichiometry into account.
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