based on this question :
http://i825.photobucket.com/albums/z.../blablabal.jpgi tried to answer the question as follow :
My answer for the first part of the question :
http://i825.photobucket.com/albums/z...bey/ffffff.jpgMy answer for the second part of the question :
http://i825.photobucket.com/albums/z...ffffffffff.jpg
The assumption is bad. This is because the most probable distribution will effectively count, in this case the {4,1,0,1,0} state is the most probable state, and we will have S=k ln WD*., where WD* is 30.
my problem is really i didn't understand the last part of the question...this is my other attempt for the second part:
Since all the states are equiprobable to occur, the probability of the 1st level is 1/6 x 5 = 5/6 and the probability of the 5th level is 1/6 x 1 = 1/6 while the arrangement factor, W for the 1st level is (6 x 5 x 4 x 3 x 2)/5! = 6 and the arrangement factor, W for the 5th level is = 6!/1! = 720.... is that means the probability for 1st level is 6/726 and the probability for the 5th level is 720/726?? i get confuse with the earlier probability and the arrangement factor??? what it has to be related with entropy?
anyone can clarify it?
and the arrangement factor = probabalility iff all the molecules are at T = 0 which means S = 0.... based on the example. probability = 1/6 x 6 = 1 and the arrangement factor, W = 6! / 6! = 1...
is my understanding towards the question is correct or I just misunderstanding it???
ANYONE CAN CLARIFY IT??? PLZ3X
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Topic: entropy and arrangement factor,W (PLEASE HELP) (Read 3423 times)